A is 6 times as fast as B and takes 100 days less to complete a work than B. Find the total number of days taken by A and B to complete the work?

Submitted by: Administrator
A completed work in 100 days before and A is 6 times faster than B..

let total days to work is n.

A=6B;

A=(n-100) days taken to complete the work;

where as B=n days ;

A=(B-100)

therefore B=A+100;

A=6(A+100);

A=6A+600;

-600=6A-A

-600=5A

A=-600/5

A=300

B=400;
Submitted by: Administrator

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