A is 6 times as fast as B and takes 100 days less to complete a work than B. Find the total number of days taken by A and B to complete the work?
Submitted by: AdministratorA completed work in 100 days before and A is 6 times faster than B..
let total days to work is n.
A=6B;
A=(n-100) days taken to complete the work;
where as B=n days ;
A=(B-100)
therefore B=A+100;
A=6(A+100);
A=6A+600;
-600=6A-A
-600=5A
A=-600/5
A=300
B=400;
Submitted by: Administrator
let total days to work is n.
A=6B;
A=(n-100) days taken to complete the work;
where as B=n days ;
A=(B-100)
therefore B=A+100;
A=6(A+100);
A=6A+600;
-600=6A-A
-600=5A
A=-600/5
A=300
B=400;
Submitted by: Administrator
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