Given d value of log 3.142 & log 3.143.
To find the value of log 3.141
Submitted by: AdministratorHere given
log 3.142=x, log 3.143=y;
10^x=3.142----------eqn 1
10^y=3.143----------eqn 2
Subtracting eqn 2-1 ;
.001= 10^y-10^x
and again subtracting
3.142-.001 =3.141
the answer is log 3.141=log( 10^x-(10^y-10^x))
log 3.141=log(2*10^x-10^y)
Submitted by: Administrator
log 3.142=x, log 3.143=y;
10^x=3.142----------eqn 1
10^y=3.143----------eqn 2
Subtracting eqn 2-1 ;
.001= 10^y-10^x
and again subtracting
3.142-.001 =3.141
the answer is log 3.141=log( 10^x-(10^y-10^x))
log 3.141=log(2*10^x-10^y)
Submitted by: Administrator
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