How do you find the refractive index of a liquid by using total internal reflection?
Submitted by: AdministratorUsing Snell's law, n (1) = (n (2) x sin angle (2)) / sin angle (1).
n (1) = The refractive index of the more optically dense medium.
n (2) = The refractive index of the less optically dense medium.
angle (1) = The critical angle of the two mediums.
angle (2) = 90 degrees since when light is at the critical angle it undergoes total internal reflection.
Since sin 90= 1, this can be ignored, resulting in n (1) = n (2) / sin angle (1)
Submitted by: Administrator
n (1) = The refractive index of the more optically dense medium.
n (2) = The refractive index of the less optically dense medium.
angle (1) = The critical angle of the two mediums.
angle (2) = 90 degrees since when light is at the critical angle it undergoes total internal reflection.
Since sin 90= 1, this can be ignored, resulting in n (1) = n (2) / sin angle (1)
Submitted by: Administrator
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