How to solve questions which involves arthematic operations on alphabets like
xxxx
yyyy
+zzzz
======
yxxxz
======
Submitted by: AdministratorR4 R3 R2 R1
x x x x
y y y y
+ z z z z
---------------------------------
y x x x z
A4 A3 A2 A1
--------------------------------
FIRST EQ: FROM ROW R1
X+Y+Z=10+Z ------>(1)
FROM ROW R2:
X+Y+Z+1= X+10;
THEN Y+Z=9------->(2)
FROM ROW R3:
SAME AS ABOVE R2 Y+Z=-1;
FROM ROW R4:
HERE Y VALUE IS 1.
SUM OF X,Y,Z IS LESS THEN 20 WHY BECAUSE X,Y,Z VALUES ARE BELOW TEN AND NOT REPEATABLE.
*X+Y+Z<20 MEANS 20=10 SO WE CAN GET Y VALUE FROM
ROW R4 : Y IS THE CARRY OF (X+Y+Z+1) THIS IS LESS THEN 20 GREATER
THAN 10 SO WE CAN TAKE Y=1;
SUBSTITUTE Y VALUE IN EQ (1): X+Y+Z=Z+10;
1+X=10;
THEN
X=9;
THEN SUBSTITUTE Y VALUE IN EQ(2):
Y+Z=9:
1+Z=9;
THEN Z=8:
RESULT IS:X=9,Y=1,Z=8.
Submitted by: Administrator
x x x x
y y y y
+ z z z z
---------------------------------
y x x x z
A4 A3 A2 A1
--------------------------------
FIRST EQ: FROM ROW R1
X+Y+Z=10+Z ------>(1)
FROM ROW R2:
X+Y+Z+1= X+10;
THEN Y+Z=9------->(2)
FROM ROW R3:
SAME AS ABOVE R2 Y+Z=-1;
FROM ROW R4:
HERE Y VALUE IS 1.
SUM OF X,Y,Z IS LESS THEN 20 WHY BECAUSE X,Y,Z VALUES ARE BELOW TEN AND NOT REPEATABLE.
*X+Y+Z<20 MEANS 20=10 SO WE CAN GET Y VALUE FROM
ROW R4 : Y IS THE CARRY OF (X+Y+Z+1) THIS IS LESS THEN 20 GREATER
THAN 10 SO WE CAN TAKE Y=1;
SUBSTITUTE Y VALUE IN EQ (1): X+Y+Z=Z+10;
1+X=10;
THEN
X=9;
THEN SUBSTITUTE Y VALUE IN EQ(2):
Y+Z=9:
1+Z=9;
THEN Z=8:
RESULT IS:X=9,Y=1,Z=8.
Submitted by: Administrator
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