If the list price of a book is reduced by Rs. 5, then a person can buy 5 more books for Rs. 300. The original cost of the book is
(1) Rs. 15
(2) Rs. 20
(3) Rs. 25
(4) Rs. 30
Submitted by: AdministratorLet 'x' be the no of book that we buy with 5 rupee less from the original book price and we buy 5 more books with the rest money each costing original book price.
so the no of cases arises are
Case 1:
x(15-5)+5(15)=300
Solving this equation we get the value of x =22.5 (which is a fraction value)
so this case is not possible.
Case 2:
x(20-5)+5(20)=300
Solving this equation we get the value of x =13.33 (which is a fraction value)
so this case is not possible.
Case 3:
x(25-5)+5(25)=300
Solving this equation we get the value of x =8.75 (which is a fraction value)
so this case is not possible.
Case 4:
x(30-5)+5(30)=300
Here we get the value of x =6 (which can be possibly a no. of book, so the original price of the book is 30).
Submitted by: Administrator
so the no of cases arises are
Case 1:
x(15-5)+5(15)=300
Solving this equation we get the value of x =22.5 (which is a fraction value)
so this case is not possible.
Case 2:
x(20-5)+5(20)=300
Solving this equation we get the value of x =13.33 (which is a fraction value)
so this case is not possible.
Case 3:
x(25-5)+5(25)=300
Solving this equation we get the value of x =8.75 (which is a fraction value)
so this case is not possible.
Case 4:
x(30-5)+5(30)=300
Here we get the value of x =6 (which can be possibly a no. of book, so the original price of the book is 30).
Submitted by: Administrator
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