In two dimensional array X(7,9) each element occupies 2 bytes of memory.If the address of first element X(1,1)is 1258 then what will be the address of the element X(5,8)?
Submitted by: Administratorhere, the address of first element x[1][1] is 1258 and also 2 byte of memory is given.now, we have to solve the address of element x[5][8], therefore, 1258+ 5*8*2 = 1258+80 = 1338 so the answer is 1338.
Submitted by: Administrator
Submitted by: Administrator
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