The length of a rectangle is increased by 60%. By what % would the width have to be decreased to maintain the same area?

Submitted by: Administrator
Let the length be L and breadth be B...therefore initial area ia A=L*B
Now if we increase length by 60%, the new length will be L+3L/5...
Let the decreased amount of breadth be x...
since the area is same in both the cases, we can equate the area as
L*B=8L/5(B-x)...Solving this we get x as 3/8...which is nothing but 37.5%
Therefore the breadth shld be decreased by 37.5%
Submitted by: Administrator

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