What should be the value of a, in the polynomials x2 - 11x + a and x2 - 14x + 2a, so that these two polynomials have common factors.
A. 24
B. 1
C. -1
D. 1/2
Submitted by: Administrator(x-b)*(x-c)=x2-11x+a-------(1)
b+c=11
bc=a
(x-b)*(x-d)=x2-14x+2a.........(2)
b+d=14
bd=2a
solving we get
b=8
c=3
d=6
which gives
a=24
Submitted by: Administrator
b+c=11
bc=a
(x-b)*(x-d)=x2-14x+2a.........(2)
b+d=14
bd=2a
solving we get
b=8
c=3
d=6
which gives
a=24
Submitted by: Administrator
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