When would local $_ in a function ruin your day?
Submitted by: AdministratorWhen your caller was in the middle for a while(m//g) loop
The /g state on a global variable is not protected by running local on it. That'll teach you to stop using locals. Too bad $_ can't be the target of a my() -- yet.
Submitted by: Administrator
The /g state on a global variable is not protected by running local on it. That'll teach you to stop using locals. Too bad $_ can't be the target of a my() -- yet.
Submitted by: Administrator
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