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Telecommunications Interview Question:
What is the maximal decimal number that can be accommodated in a byte?
a) 128
b) 256
c) 255
d) 512
Submitted by: AdministratorITS 256.
SINCE, 1 BYTE=8 BITS
THE LOGIC IS 2^8=256(2 TO THE POWER OF 8)
Submitted by: Administrator
SINCE, 1 BYTE=8 BITS
THE LOGIC IS 2^8=256(2 TO THE POWER OF 8)
Submitted by: Administrator
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