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C++ Operator Overloading Interview Question:
Why we use the "dynamic_cast" type conversion?
a) result of the type conversion is a valid
b) to be used in low memory
c) result of the type conversion is a invalid
d) None of the mentioned
Submitted by: Murtazaa) result of the type conversion is a valid
Submitted by: Murtaza
Submitted by: Murtaza
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