Question:
The rate of a reaction doubles when the temperature changes from 27C to 37C. Calculate the energy of activation.

Option A):
54.1 kJ mol^-1
Option B):
53.6 kJ mol^-1
Option C):
52.6 kJ mol^-1
Option D):
54.6 kJ mol^-1

Correct Answer is Option B):
53.6 kJ mol^-1