Directions:

#include<stdio.h>
#define int char 
void main()
{
      int i = 65;
      printf("sizeof(i)=%d", sizeof(i));
}

Question:
What will be the output of the program?

Option A):
None
Option B):
Compiler Error
Option C):
sizeof(i)=2
Option D):
sizeof(i)=1

Correct Answer is Option D):
sizeof(i)=1

Explanation:
Since the #define replaces the string int by the macro char.
So, here i is a variable of type char and not int.