You are not logged in.

#1 2015-04-20 07:48:53

hasnain
Administrator
From: Chichawatni
Registered: 2014-10-13
Posts: 8,355
Website

Addition Sum:

Directions:
15-6.gif

Question:
In the above correctly worked addition sum, A,B,C and D represent different digits, and all the digits in the sum are different. What is the sum of A,B,C and D?

Option A):
23
Option B):
18
Option C):
16
Option D):
22

Correct Answer is Option D):
22

Explanation:
First you must realize that the sum of two 2-digit numbers cannot be more that 198 (99 + 99). Therefore in the given problem D must be 1.
Now use trial and error to satisfy the sum 5A + BC = 143
A + C must give 3 in the units place, but neither can be 1 since all the digits have to be different. Therefore A + C = 13.
With one to carry over into the tens column, 1 + 5 + B = 14, and B = 8.
A + C + B + D = 13 + 8 + 1 = 22


Failure is the first step towards seccess.

2015-04-20 07:48:53

Advertisement
Ads By Google

Re: Addition Sum:



\n

Board footer