How many moles of HCl are present in .70 L of a .33 M HCl?
Submitted by: Administrator► First, remember definition of M (moles), M = moles of species / L.
0.33 M = 0.33 moles HCl / L
► Then, multiple your volume by the molar concentration:
0.33 moles HCl / L x 0.70 L = 0.231 moles HCl
It is helpful to carry the units with your calculations. That way you can check that numerators and denominators cancel to give you the units of your answer.
Submitted by:
0.33 M = 0.33 moles HCl / L
► Then, multiple your volume by the molar concentration:
0.33 moles HCl / L x 0.70 L = 0.231 moles HCl
It is helpful to carry the units with your calculations. That way you can check that numerators and denominators cancel to give you the units of your answer.
Submitted by:
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