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Role-specific C++ Operator Overloading Interview Questions & Answers:

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1. Pick the other name of operator function.
a) function overloading
b) operator overloading
c) member overloading
d) None of the mentioned

b) operator overloading

2. How to declare operator function?
a) operator operator sign
b) operator
c) operator sign
d) None of the mentioned

a) operator operator sign

3. Which of the following statements is NOT valid about operator overloading?
a) Only existing operators can be overloaded.
b) Overloaded operator must have at least one operand of its class type.
c) The overloaded operators follow the syntax rules of the original operator.
d) None of the mentioned

d) None of the mentioned

4. Operator overloading is:
a) making c++ operator works with objects
b) giving new meaning to existing operator
c) making new operator
d) both a & b

d) both a & b

5. The output of this program?

#include <iostream>
using namespace std;
ostream & operator<<(ostream & i, int n)
{
return i;
}
int main()
{
cout << 5 << endl;
cin.get();
return 0;
}
a) 5
b) 6
c) error
d) runtime error

c) error

6. Output of this program?

#include <iostream>
using namespace std;
class myclass
{
public:
int i;
myclass *operator->()
{return this;}
};
int main()
{
myclass ob;
ob->i = 10;
cout << ob.i << " " << ob->i;
return 0;
}
a) 10 10
b) 11 11
c) error
d) runtime error

a) 10 10

7. Output of this program?

#include <iostream>
using namespace std;
class Integer
{
int i;
public:
Integer(int ii) : i(ii) {}
const Integer
operator+(const Integer& rv) const
{
cout << "operator+" << endl;
return Integer(i + rv.i);
}
Integer&
operator+=(const Integer& rv)
{
cout << "operator+=" << endl;
i += rv.i;
return *this;
}
};
int main()
{
int i = 1, j = 2, k = 3;
k += i + j;
Integer ii(1), jj(2), kk(3);
kk += ii + jj;
}
a) operator+
operator+=
b) operator+=
operator+
c) operator+
operator+
d) None of the mentioned

a) operator+
operator+=

8. Output of Program?

#include <iostream>
using namespace std;
class sample
{
public:
int x, y;
sample() {};
sample(int, int);
sample operator + (sample);
};
sample::sample (int a, int b)
{
x = a;
y = b;
}
sample sample::operator+ (sample param)
{
sample temp;
temp.x = x + param.x;
temp.y = y + param.y;
return (temp);
}
int main ()
{
sample a (4,1);
sample b (3,2);
sample c;
c = a + b;
cout << c.x << "," << c.y;
return 0;
}
a) 5, 5
b) 7, 3
c) 3, 7
d) None of the mentioned

b) 7, 3

9. Which of the following operators can't be overloaded?
a) ::
b) +
c) -
d) []

a) ::

10. Pick out the correct syntax of operator conversion.
a) operator float()const
b) operator float()
c) operator const
d) None of the mentioned

a) operator float()const

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