Do you know how to calculate how many moles of glucose present in 320 mL of 5.0 M of glucose solution?
Submitted by: MuhammadFirst step: Convert the volume from millilitres to liters
320 X (1 litre/1000mL) = 0.320 L solution
Second use the formula = M x V
= 5.0 moles glucose/ litre solution X 0.320 L solution
= 1.6 moles of glucose present in 320mL of solution
Submitted by: Muhammad
320 X (1 litre/1000mL) = 0.320 L solution
Second use the formula = M x V
= 5.0 moles glucose/ litre solution X 0.320 L solution
= 1.6 moles of glucose present in 320mL of solution
Submitted by: Muhammad
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