How do I declare an array of N pointers to functions returning pointers to functions returning pointers to characters?
Submitted by: AdministratorAnswer1
If you want the code to be even slightly readable, you will use typedefs.
typedef char* (*functiontype_one)(void);
typedef functiontype_one (*functiontype_two)(void);
functiontype_two myarray[N]; //assuming N is a const integral
Answer2
char* (* (*a[N])())()
Here a is that array. And according to question no function will not take any parameter value.
Submitted by: Administrator
If you want the code to be even slightly readable, you will use typedefs.
typedef char* (*functiontype_one)(void);
typedef functiontype_one (*functiontype_two)(void);
functiontype_two myarray[N]; //assuming N is a const integral
Answer2
char* (* (*a[N])())()
Here a is that array. And according to question no function will not take any parameter value.
Submitted by: Administrator
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