Explain example of Central Limit Theorem?
Submitted by: AdministratorGiven that the population of men has normally distributed weights, with a mean of 173 lb and a standard deviation of 30 lb, find the probability that
a. if 1 man is randomly selected, his weight is greater than 180 lb.
b. if 36 different men are randomly selected, their mean weight is greater that 180 lb.
Solution: a) z = (x - μ)/ σ = (180-173)/30 = 0.23
For normal distribution P(Z>0.23) = 0.4090
b) σ x̄ = σ/√n = 20/√ 36 = 5
z= (180-173)/5 = 1.40
P(Z>1.4) = 0.0808
Submitted by:
a. if 1 man is randomly selected, his weight is greater than 180 lb.
b. if 36 different men are randomly selected, their mean weight is greater that 180 lb.
Solution: a) z = (x - μ)/ σ = (180-173)/30 = 0.23
For normal distribution P(Z>0.23) = 0.4090
b) σ x̄ = σ/√n = 20/√ 36 = 5
z= (180-173)/5 = 1.40
P(Z>1.4) = 0.0808
Submitted by:
Read Online Statistician Job Interview Questions And Answers
Top Statistician Questions
☺ | Explain frequentist? |
☺ | Explain about binary search? |
☺ | Explain linear regression? |
☺ | Explain mode? |
☺ | Explain sampling methods? |
Top School Education Categories
☺ | Mathematics Interview Questions. |
☺ | GMAT Interview Questions. |
☺ | Metallurgy Interview Questions. |
☺ | Polio Eradication Officer Interview Questions. |
☺ | Physical Education Interview Questions. |