One train leaves Los Angeles at 15mph heading for New York.
Another train leaves from New York at 20mph heading for Los Angeles on the same track. If a bird, flying at 25mph, leaves from Los Angeles at the same time as the train and
flies back and forth between the two trains until they collide, how far will the bird have traveled?
Submitted by: AdministratorActually they should mention distance between the two stations, but i searched in Internet and i found the distance between the stations is 2450 miles.
So the time taken for both trains to meet is
Time taken=distance between them/Relative speed of both trains in opp direction(Sum of speeds)=2450/35=70 hours.
so for these 70 hrs the bird will be travelling here and there. so distance traveled for 70 hrs = 70*25=1750 miles.
So answer is 1750 miles.
Submitted by: Administrator
So the time taken for both trains to meet is
Time taken=distance between them/Relative speed of both trains in opp direction(Sum of speeds)=2450/35=70 hours.
so for these 70 hrs the bird will be travelling here and there. so distance traveled for 70 hrs = 70*25=1750 miles.
So answer is 1750 miles.
Submitted by: Administrator
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