There are two numbers in the ratio 8:9. if the smaller of the two numbers is increased by 12 and the larger number is reduced by 19 thee the ratio of the two numbers is 5:9.
Find the larger number?
Submitted by: AdministratorLet Smallest number be x & largest number be y.
so X/y=8/9
x=8/9y
(x+12)/(y-19)=5/9
(8/9y+12)/(y-19)=5/9
8/9y^2-19*8/9y+12y-12*19-5/9=0
Submitted by: Administrator
so X/y=8/9
x=8/9y
(x+12)/(y-19)=5/9
(8/9y+12)/(y-19)=5/9
8/9y^2-19*8/9y+12y-12*19-5/9=0
Submitted by: Administrator
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