1. Can you tender a one rupee note in such a manner that there shall be total 50 coins but none of them would be 2 paise coins?

45 one paisa coins, 2 five paise coins, 2 ten paise coins, and 1 twenty-five paise coins

paisa no. of coins
1 40 = 40
5 8 = 40
10 2 = 20
--------------------------------
50 100

2. If time at this moment is 9 P.M., what will be the time 23999999992 hours later?

1 P.M.24 billion hours later, it would be 9 P.M. and 8 hours before that itwould be 1 P.M.

4. If s(a) denotes square root of a, find the value of s(12+s(12+s(12+ ...... upto infinity?

4 Explanation :
Let x = s(12+s(12+s(12+..... )
We can write x = s(12+x). i.e., x^2 = 12 + x. Solving this quadratic equation, we get x = -3 or x=4. Sum cannot be -ve and hence sum = 4.

6. What is the sum of all numbers between 100 and 1000 which are divisible by 14?

35392Explanation : The number closest to 100 which is greater than 100 and divisible by14 is 112, which is the first term of the series which has to be summed.The number closest to 1000 which is less than 1000 and divisible by 14 is 994,which is the last term of the series.112 + 126 + .... + 994 = 14(8+9+ ... + 71) = 35392.

7. A fast typist can type some matter in 2 hours and a slow typist can type the same in 3 hours. If both type combinely, in how much time will they finish?

1 hr 12 minExplanation : The fast typist's work done in 1 hr = 1/2 The slow typist's work done in 1 hr = 1/3 If they work combinely, work done in 1 hr = 1/2+1/3 = 5/6 So, the work will be completed in 6/5 hours. i.e., 1+1/5 hours = 1hr 12 min.

8. Each side of a rectangle is increased by 100% .By what percentage does the areaincrease?

300%.

100% of l=l
new length = l+l= 2l
new width = b+b= 2b
old area = l*b
new area = 2l * 2b
= 4lb
therfore increase in area= 400%

9. A contractor agreeing to finish a work in 150 days, employed 75 men each working 8 hours daily. After 90 days, only 2/7 of the work was completed. Increasing the number of men by ________ each working now for 10 hours daily, the work can be completed in time?

150 men.Explanation:One day?s work = 2 / (7 * 90)One hour?s work = 2 / (7 * 90 * 8)One man?s work = 2 / (7 * 90 * 8 * 75)The remaining work (5/7) has to be completed within 60 days, because thetotal number of days allotted for the project is 150 days.So we get the equation(2 * 10 * x * 60) / (7 * 90 * 8 * 75) = 5/7 where x is the number of menworking after the 90th day.We get x = 225Since we have 75 men already, it is enough to add only 150 men..

90*75*8 = 2/7(work)
now 5/7 th of work left..
so 60*(75+x)*10 =5/7(work)
x=no of workers..
devide the two equations..
x=150

10. 7^101+18^101 is a multiple of
a.15
b.25
c.35
d.45?

"Clearly," Naveen Reddy is an idiot. 7^101 + 18^101 is not the same as 7*101 + 18*101