**1. A man walks 3km east then 5km north then 8km east. Now how far is he from the starting point**

if u draw a rectangle of length of total(3+8) km and breadth 5km and draw a diagonal from the starting to ending point, by Pythagaros Theorem, square(hyp)=square(the both sides)

Therefore, 25+121=sqrt(answer)

it comes to be 12.083km

The right question is:A ship started from port and moving with I mph and another ship started from L and moving with H mph. At which place these two ships meet? !_____!_____!_____!_____!_____!_____! port G H I J K L

223 is answer

B-C is bitwise addition of B and 2s compliment of C

then bitwise union of A with abover result gives the ans as 1101 1111 which

has decimal value of 223.

-1,-1,-1,-1, -1,-1

**5. Wind flows 160 miles in 330 min, for 80 miles how much time required?**

answer as 165

as

160 miles are covered in 330 min

1 mile will be covered in 330/160 min

Hence 80 miles will be covered in 80*330/160 =165 min.

3*1=3

instead of 1 if he divided by 3

then he will get 1only

3*(1/3)=1

Apply t=5, ans=33.7 for t=8, ans=46.7

The differenc between the two, 46.7-33.7=13 is the answr upto my knowledge.

this can be solved by using the rule of cross multiplication i guess....

to get a shadow of G ft the ht of the building should be D

hence, for the shadow to be C ft, the height of the building should be CxD/G

**9. 27(deg) 6 43.1545(deg) 31 4.3find the degrees when the time is 3o clock?**

The angel between the minutes and hour hand would be 45 degree at 3'0 clock

for 1st machine 100-25 ie 75

for 2nd machine 100-20 ie 80

for 3rd machine its 100-10 ie 95

so efficiency in rev = (90*80*75)/10000

=54

so fuel economy =100-54

=46