How many 5 digit numbers can be formed using the digits 1, 2, 3, 4, 5 (but with repetition) that are divisible by 4?
Submitted by: AdministratorDivisibility rule of 4 is last two digits are divisible by 4
so in 5 digit no last two digit should always be 12,24,32,44,52;
(any one of them may be)
so for last two digits 5 ways are possible ;
since repetion are allowed then for 3rs place form right there are also 5 ways so in 3rd place either of 1,2,3,4,5 is possible;
simillarly at 4 rth place either of 1,2,3,4,5 is possible so again 5 ways are possible
simillarly at 5th place also 5 ways are possible
so total no are: 5*5*5*5=625
Submitted by: Administrator
so in 5 digit no last two digit should always be 12,24,32,44,52;
(any one of them may be)
so for last two digits 5 ways are possible ;
since repetion are allowed then for 3rs place form right there are also 5 ways so in 3rd place either of 1,2,3,4,5 is possible;
simillarly at 4 rth place either of 1,2,3,4,5 is possible so again 5 ways are possible
simillarly at 5th place also 5 ways are possible
so total no are: 5*5*5*5=625
Submitted by: Administrator
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