In a right-angled triangle, the square of the hypotenuse is twice the product of the other two sides. Then one of the acute angles of the triangle is…
A. 450
B. 300
C. 600
D. 150
Submitted by: Administrator3 sides are p,q, sqrt(2pq).
now if it is sright-angle then 2pq=p^2+q^2;
cos(angle)=sqrt(p/2q);
sin(angle)=sqrt(q/2p);
So sin(2*angle)=2*sin(angle)*cos(angle);
sin(2*angle)=1;
So angle=45;
Submitted by: Administrator
now if it is sright-angle then 2pq=p^2+q^2;
cos(angle)=sqrt(p/2q);
sin(angle)=sqrt(q/2p);
So sin(2*angle)=2*sin(angle)*cos(angle);
sin(2*angle)=1;
So angle=45;
Submitted by: Administrator
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