Suppose a train passes two cars moving in the direction at 45km/hr and 50km/hr in 36 sec and 54 sec respectively. What is the length of the train?
Submitted by: Administratortrain crossed the car with less speed in less time and the car with high speed in more time.i.e train and two cars going in the same direction.
hence 1st car
L/((S-45)*5/18)=36 i.e L=10S-450
similarly for 2nd car
L=15S-750
BY solving these two equations we get length of the train L=150mtrs
Submitted by: Administrator
hence 1st car
L/((S-45)*5/18)=36 i.e L=10S-450
similarly for 2nd car
L=15S-750
BY solving these two equations we get length of the train L=150mtrs
Submitted by: Administrator
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