What is the sum of all the four digit numbers formed using the digits 0, 1, 2 and 3. None of the two digits should be repeated?
Submitted by: AdministratorProcess of solving
From these four digits '0' cannot be at first place to form four digit number
so we have 1, 2, or 3 can be at thousand's place
keeping one digit at thousand place can have 6 different four digit number
so that means
1000*6 + 2000* 6 + 3000* 6 = 36000
Now come to hundred's place we can have all four digit at this place , '0' will not contribute any thing to sum so in all four digits number 1,2,3 will be at 4 times on same place
so that means
100*4 + 200* 4 + 300 * 4= 2400
Now come to tenth's place ...same as hundred
so
10*4 + 20*4 + 30*4= 240
same for unit place
1*4 + 2*4 + 3*4= 24
in last if you add whole the total sum of all possible four digit number formed is 38664
Submitted by: Administrator
From these four digits '0' cannot be at first place to form four digit number
so we have 1, 2, or 3 can be at thousand's place
keeping one digit at thousand place can have 6 different four digit number
so that means
1000*6 + 2000* 6 + 3000* 6 = 36000
Now come to hundred's place we can have all four digit at this place , '0' will not contribute any thing to sum so in all four digits number 1,2,3 will be at 4 times on same place
so that means
100*4 + 200* 4 + 300 * 4= 2400
Now come to tenth's place ...same as hundred
so
10*4 + 20*4 + 30*4= 240
same for unit place
1*4 + 2*4 + 3*4= 24
in last if you add whole the total sum of all possible four digit number formed is 38664
Submitted by: Administrator
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